What is 2+y^2-6x+2y+1=0 ?

The solution to 2+y^2-6x+2y+1=0 is Parabola with (h,k)=(1/3 ,-1),p= 3/2

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2+y^2-6x+2y+1=0

2 + y^{2} - 6 x + 2 y + 1 = 0

(h, k) = (\frac{1}{3}, - 1), p = \frac{3}{2}

Solution steps

2 + y^{2} - 6 x + 2 y + 1 = 0

Rewrite

2 + y^{2} - 6 x + 2 y + 1 = 0

in the standard form

4 \cdot \frac{3}{2} (x - \frac{1}{3}) = (y - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{3}, - 1), p = \frac{3}{2}

x^{2} - 76 x + 30 y - 100 = 0

f (x) = - x^{2} - 2 x + 24

(x - 0)^{2} = - 12 (y - 5)

y^{2} + 2 y + 4 x - 6 = 0

(y - 2)^{2} = 2 (x - 3)

What is 2+y^2-6x+2y+1=0 ?
The solution to 2+y^2-6x+2y+1=0 is Parabola with (h,k)=(1/3 ,-1),p= 3/2