What is f(x)(x)^{-1}=5(x-2) ?

The solution to f(x)(x)^{-1}=5(x-2) is Parabola with (h,k)=(1,-5),p= 1/20

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f(x)(x)^{-1}=5(x-2)

f (x) (x)^{- 1} = 5 (x - 2)

(h, k) = (1, - 5), p = \frac{1}{20}

Solution steps

y x^{- 1} = 5 (x - 2)

Rewrite

y x^{- 1} - 5 (x - 2) = 0

in the standard form

4 \cdot \frac{1}{20} (y - (- 5)) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, - 5), p = \frac{1}{20}

2 x^{2} + 4 y - 6 = 0

h = x - (\frac{y - k}{a})^{2}

r^{2} - 4 r - t = 0

(x - 2)^{2} = 5 (y + 3)

x^{2} - 6 x - 12 y - 11 = 0

What is f(x)(x)^{-1}=5(x-2) ?
The solution to f(x)(x)^{-1}=5(x-2) is Parabola with (h,k)=(1,-5),p= 1/20