What is 3x^2+11s+10=0 ?

The solution to 3x^2+11s+10=0 is Parabola with (h,k)=(0,-10/11),p=-11/12

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3x^2+11s+10=0

3 x^{2} + 11 s + 10 = 0

(h, k) = (0, - \frac{10}{11}), p = - \frac{11}{12}

Solution steps

3 x^{2} + 11 s + 10 = 0

Rewrite

3 x^{2} + 11 s + 10 = 0

in the standard form:

4 (- \frac{11}{12}) (s - (- \frac{10}{11})) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - \frac{10}{11}), p = - \frac{11}{12}

17 x^{2} + 25 y = 425

x - 5 x + y^{2} + 7 x - 9 = 0

y^{2} + 4 x + 2 y + 9 = 0

\frac{2}{5} y^{2} + \frac{5}{3} x = 1

(x - 3)^{2} = 4 (- 8) (y - 3)

What is 3x^2+11s+10=0 ?
The solution to 3x^2+11s+10=0 is Parabola with (h,k)=(0,-10/11),p=-11/12