What is ((y-2)^2)/9+((x+1/2))/9 =1 ?

The solution to ((y-2)^2)/9+((x+1/2))/9 =1 is Parabola with (h,k)=(17/2 ,2),p=-1/4

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((y-2)^2)/9+((x+1/2))/9 =1

\frac{( y - 2 ) ^{2}}{9} + \frac{( x + \frac{1}{2} )}{9} = 1

(h, k) = (\frac{17}{2}, 2), p = - \frac{1}{4}

Solution steps

\frac{( y - 2 ) ^{2}}{9} + \frac{x + \frac{1}{2}}{9} = 1

Rewrite

\frac{( y - 2 ) ^{2}}{9} + \frac{x + \frac{1}{2}}{9} = 1

in the standard form:

4 (- \frac{1}{4}) (x - \frac{17}{2}) = (y - 2)^{2}

Therefore parabola properties are:

(h, k) = (\frac{17}{2}, 2), p = - \frac{1}{4}

a - f (x) = x^{2}

a^{2} = 800 c m^{2}

8 (y - 2) = (x - 3)^{2}

x^{2} - 2 x + 3 y - 8 = 0

y^{2} - 48 x = 0

What is ((y-2)^2)/9+((x+1/2))/9 =1 ?
The solution to ((y-2)^2)/9+((x+1/2))/9 =1 is Parabola with (h,k)=(17/2 ,2),p=-1/4