What is (s^2)/2 =(283.1t+C) ?

The solution to (s^2)/2 =(283.1t+C) is Parabola with (h,k)=(0,-0.00353…C),p=141.55

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(s^2)/2 =(283.1t+C)

\frac{s ^{2}}{2} = (283.1 t + C)

(h, k) = (0, - 0.00353 \dots C), p = 141.55

Solution steps

\frac{s ^{2}}{2} = (283.1 t + C)

Rewrite

\frac{s ^{2}}{2} = (283.1 t + C)

in the standard form:

4 \cdot 141.55 (t - (- 0.00353 \dots C)) = (s - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 0.00353 \dots C), p = 141.55

y - 2 x^{2} - 4 x + 7 = 0

α^{2} + 2 β = 1

(x 7) = - 8 (y - 1.5)^{2}

6 y^{2} + 8 x + 24 y + 44 = 0

(x - 3)^{2} = 8 (y + 4)

What is (s^2)/2 =(283.1t+C) ?
The solution to (s^2)/2 =(283.1t+C) is Parabola with (h,k)=(0,-0.00353…C),p=141.55