What is (y+5)^{(2)}=-2(x-7) ?

The solution to (y+5)^{(2)}=-2(x-7) is Parabola with (h,k)=(7,-5),p=-1/2

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(y+5)^{(2)}=-2(x-7)

(y + 5)^{(2)} = - 2 (x - 7)

(h, k) = (7, - 5), p = - \frac{1}{2}

Solution steps

(y + 5)^{2} = - 2 (x - 7)

Rewrite

(y + 5)^{2} = - 2 (x - 7)

in the standard form:

4 (- \frac{1}{2}) (x - 7) = (y - (- 5))^{2}

Therefore parabola properties are:

(h, k) = (7, - 5), p = - \frac{1}{2}

2 y^{2} - x - 3 y = 0

(x - 3)^{2} = 8 (y + 5)

- y^{2} + x = 1

x^{2} + 6 x + 16 y + 25 = 0

2 x = y^{2} - 2 y + \frac{1}{3}

What is (y+5)^{(2)}=-2(x-7) ?
The solution to (y+5)^{(2)}=-2(x-7) is Parabola with (h,k)=(7,-5),p=-1/2