What is x=(y/2)^2+(y/2)^2 ?

The solution to x=(y/2)^2+(y/2)^2 is Parabola with (h,k)=(0,0),p= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x=(y/2)^2+(y/2)^2

x = (\frac{y}{2})^{2} + (\frac{y}{2})^{2}

(h, k) = (0, 0), p = \frac{1}{2}

Solution steps

x = (\frac{y}{2})^{2} + (\frac{y}{2})^{2}

Rewrite

x = (\frac{y}{2})^{2} + (\frac{y}{2})^{2}

in the standard form

4 \cdot \frac{1}{2} (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{2}

y \leq - x^{2} + 2 x + 3

(y - 3)^{2} = 16 (x + 6)

x^{2} = - 80 y

y \leq - 2 x^{2} + 4 x - 1

x 3 x = 20 - 4 y

What is x=(y/2)^2+(y/2)^2 ?
The solution to x=(y/2)^2+(y/2)^2 is Parabola with (h,k)=(0,0),p= 1/2