What is x^2+x+2m(x)+1=0 ?

The solution to x^2+x+2m(x)+1=0 is Parabola with (h,k)=(-1/2 ,-3/8),p=-1/2

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x^2+x+2m(x)+1=0

x^{2} + x + 2 m (x) + 1 = 0

(h, k) = (- \frac{1}{2}, - \frac{3}{8}), p = - \frac{1}{2}

Solution steps

x^{2} + x + 2 y + 1 = 0

Rewrite

x^{2} + x + 2 y + 1 = 0

in the standard form

4 (- \frac{1}{2}) (y - (- \frac{3}{8})) = (x - (- \frac{1}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{2}, - \frac{3}{8}), p = - \frac{1}{2}

2 y = x^{2} - 10

f, f = 6 (x - 2) f (x)^{- 1} (x) f - 1 (x)

\frac{x - 3}{2 ^{2}} - \frac{y ^{2}}{2 ^{2}} = 1

(y - 3)^{2} = 7 (x - 8)

x = \frac{( y ^{(2)} + 5 )}{( 2 )}

What is x^2+x+2m(x)+1=0 ?
The solution to x^2+x+2m(x)+1=0 is Parabola with (h,k)=(-1/2 ,-3/8),p=-1/2