What is (5*4-1)x^2+4x+m(x)=-11 ?

The solution to (5*4-1)x^2+4x+m(x)=-11 is Parabola with (h,k)=(-2/19 ,-205/19),p=-1/76

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(5*4-1)x^2+4x+m(x)=-11

(5 \cdot 4 - 1) x^{2} + 4 x + m (x) = - 11

(h, k) = (- \frac{2}{19}, - \frac{205}{19}), p = - \frac{1}{76}

Solution steps

(5 \cdot 4 - 1) x^{2} + 4 x + y = - 11

Rewrite

(5 \cdot 4 - 1) x^{2} + 4 x + y = - 11

in the standard form

4 (- \frac{1}{76}) (y - (- \frac{205}{19})) = (x - (- \frac{2}{19}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{2}{19}, - \frac{205}{19}), p = - \frac{1}{76}

x^{2} + 2 x - 6 y - 17 = 0

(y + 5)^{2} = - 12 (x + 1)

p^{2} + 12 q = 1400

(y - 5)^{2} = 36 (x - 3)

16 (x + 2) - (y + 5)^{2} = 0

What is (5*4-1)x^2+4x+m(x)=-11 ?
The solution to (5*4-1)x^2+4x+m(x)=-11 is Parabola with (h,k)=(-2/19 ,-205/19),p=-1/76