What is 5x^2+25x+10y=15 ?

The solution to 5x^2+25x+10y=15 is Parabola with (h,k)=(-5/2 , 37/8),p=-1/2

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5x^2+25x+10y=15

5 x^{2} + 25 x + 10 y = 15

(h, k) = (- \frac{5}{2}, \frac{37}{8}), p = - \frac{1}{2}

Solution steps

5 x^{2} + 25 x + 10 y = 15

Rewrite

5 x^{2} + 25 x + 10 y = 15

in the standard form

4 (- \frac{1}{2}) (y - \frac{37}{8}) = (x - (- \frac{5}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{5}{2}, \frac{37}{8}), p = - \frac{1}{2}

x^{2} - 8 x - 10 y - 4 = 0

0.2 x^{2} - 0.8 x - 0.2 = o

q^{1} = 105 - 3 p^{1} + p^{2}

x^{2} = 50 y

- x^{2} + y - 2 = 0

What is 5x^2+25x+10y=15 ?
The solution to 5x^2+25x+10y=15 is Parabola with (h,k)=(-5/2 , 37/8),p=-1/2