What is -2x^2+2x+y-1=0 ?

The solution to -2x^2+2x+y-1=0 is Parabola with (h,k)=(1/2 , 1/2),p= 1/8

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-2x^2+2x+y-1=0

- 2 x^{2} + 2 x + y - 1 = 0

(h, k) = (\frac{1}{2}, \frac{1}{2}), p = \frac{1}{8}

Solution steps

- 2 x^{2} + 2 x + y - 1 = 0

Rewrite

- 2 x^{2} + 2 x + y - 1 = 0

in the standard form

4 \cdot \frac{1}{8} (y - \frac{1}{2}) = (x - \frac{1}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{2}, \frac{1}{2}), p = \frac{1}{8}

(y - 1)^{2} = - 9 (x + 2)

(x - 7)^{2} = - 14 (\frac{y - 3}{2})

8 x^{2} + 9 x + k (x) = 0

(x - 5)^{2} = 8 (6 - y)

4 (- 3) (y - (- 1)) = (x - 3)^{2}

What is -2x^2+2x+y-1=0 ?
The solution to -2x^2+2x+y-1=0 is Parabola with (h,k)=(1/2 , 1/2),p= 1/8