What is x=1-(y+2)^2 ?

The solution to x=1-(y+2)^2 is Parabola with (h,k)=(1,-2),p=-1/4

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x=1-(y+2)^2

x = 1 - (y + 2)^{2}

(h, k) = (1, - 2), p = - \frac{1}{4}

Solution steps

x = 1 - (y + 2)^{2}

Rewrite

x = 1 - (y + 2)^{2}

in the standard form:

4 (- \frac{1}{4}) (x - 1) = (y - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (1, - 2), p = - \frac{1}{4}

\frac{s ^{2} - 2 p + 6 p}{( s + 2 )} = 1

f, f (x)^{- 1} (x) = \frac{0.75}{10 - x}

T (n) = T (n - 1) + n^{2}

2 y = - 4 \cdot (x + 2)^{2} + m + 5

g (x) = - \frac{1}{2} x^{2} - 2

What is x=1-(y+2)^2 ?
The solution to x=1-(y+2)^2 is Parabola with (h,k)=(1,-2),p=-1/4