What is (y-7.09)/(0.01)=x^2+25x ?

The solution to (y-7.09)/(0.01)=x^2+25x is Parabola with (h,k)=(-25/2 ,-25/16),p=25

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(y-7.09)/(0.01)=x^2+25x

\frac{y - 7.09}{0.01} = x^{2} + 25 x

(h, k) = (- \frac{25}{2}, - \frac{25}{16}), p = 25

Solution steps

\frac{y - 7.09}{0.01} = x^{2} + 25 x

Rewrite

\frac{y - 7.09}{0.01} = x^{2} + 25 x

in the standard form

4 \cdot 25 (y - (- \frac{25}{16})) = (x - (- \frac{25}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{25}{2}, - \frac{25}{16}), p = 25

y^{2} + 4 x = y + 8

x^{2} - 16 x - 32 y = - 224

f (x) = x^{2} + 2 x + 3

f (x) = x^{2}

f (x) = - 2 x^{2} - 2 x - 2

What is (y-7.09)/(0.01)=x^2+25x ?
The solution to (y-7.09)/(0.01)=x^2+25x is Parabola with (h,k)=(-25/2 ,-25/16),p=25