What is the vertices f(x)=3x^2 ?

The vertices f(x)=3x^2 is Minimum (0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices f(x)=3x^2

vertices

f (x) = 3 x^{2}

Minimum (0, 0)

Solution steps

y = 3 x^{2}

The parabola parameters are:

a = 3, b = 0, c = 0

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{0}{2 \cdot 3}

Simplify

x_{v} = 0

Plug in

x_{v} = 0

to find the

y_{v}

value

y_{v} = 0

Therefore the parabola vertex is

(0, 0)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 3

Minimum (0, 0)

y = 4 x^{2} - 8 x + 7

y = x^{2} - 2 x - 8

y = x^{2} - 4 x + 3

y = 2 x^{2}

x^{2} + 2 x - 1 - (2 x^{2} - 3 x + 6)