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vertices y^2=12x

Solution

vertices

y^{2} = 12 x

Solution

(h, k) = (0, 0), p = 3

Solution steps

y^{2} = 12 x

Rewrite

y^{2} = 12 x

in the standard form:

4 \cdot 3 (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = 3

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Frequently Asked Questions (FAQ)

What is the vertices y^2=12x ?
The vertices y^2=12x is (h,k)=(0,0),p=3