What is the vertices-12x^2-29x+230 ?

The vertices-12x^2-29x+230 is Maximum (-29/24 , 11881/48)

Popular >

vertices-12x^2-29x+230

vertices

- 12 x^{2} - 29 x + 230

Maximum (- \frac{29}{24}, \frac{11881}{48})

Solution steps

y = - 12 x^{2} - 29 x + 230

The parabola parameters are:

a = - 12, b = - 29, c = 230

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{( - 29 )}{2 ( - 12 )}

Simplify

x_{v} = - \frac{29}{24}

Plug in

x_{v} = - \frac{29}{24}

to find the

y_{v}

value

y_{v} = \frac{11881}{48}

Therefore the parabola vertex is

(- \frac{29}{24}, \frac{11881}{48})

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = - 12

Maximum (- \frac{29}{24}, \frac{11881}{48})

f (x) = 3 x^{2} - 6 x + 5

2 x^{2} + 4 x - 6

y = k (x - 0)^{2} + 2

y = 5 x^{2} - 3 x - 7 + 2 x^{2} - x

4 y^{2} - 48 x - 20 y = 71

What is the vertices-12x^2-29x+230 ?
The vertices-12x^2-29x+230 is Maximum (-29/24 , 11881/48)