What is the axis y^2=4x ?

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axis y^2=4x

axis

y^{2} = 4 x

y = 0

Solution steps

y^{2} = 4 x

Rewrite

y^{2} = 4 x

in the standard form:

4 \cdot 1 \cdot (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = 1

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

3 x^{2} + 12 x + 4 y^{2} - 40 y + 100 = 0

(x + 2)^{2} + (y - 4)^{2} = 25

9 x^{2} - 4 y^{2} - 72 x = 0

\frac{x ^{2}}{36} - \frac{y ^{2}}{64} = 1

9 x^{2} - 16 y^{2} = 144