What is the vertices X^2-5X-24 ?

The vertices X^2-5X-24 is Minimum (5/2 ,-121/4)

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vertices X^2-5X-24

vertices

X^{2} - 5 X - 24

Minimum (\frac{5}{2}, - \frac{121}{4})

Solution steps

y = X^{2} - 5 X - 24

The parabola parameters are:

a = 1, b = - 5, c = - 24

x_{v} = - \frac{b}{2 a}

X_{v} = - \frac{( - 5 )}{2 \cdot 1}

Simplify

X_{v} = \frac{5}{2}

Plug in

X_{v} = \frac{5}{2}

to find the

y_{v}

value

y_{v} = - \frac{121}{4}

Therefore the parabola vertex is

(\frac{5}{2}, - \frac{121}{4})

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 1

Minimum (\frac{5}{2}, - \frac{121}{4})

y = x^{2} + 8 x + 7

4 t^{2} + 1

f (x) = \frac{1}{2} (x - 1)^{2}

x^{2} + 1

2 x^{2} - 5 x + 3

What is the vertices X^2-5X-24 ?
The vertices X^2-5X-24 is Minimum (5/2 ,-121/4)