What is the vertices y=5x^2+210x-34775 ?

The vertices y=5x^2+210x-34775 is Minimum (-21,-36980)

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vertices y=5x^2+210x-34775

vertices

y = 5 x^{2} + 210 x - 34775

Minimum (- 21, - 36980)

Solution steps

y = 5 x^{2} + 210 x - 34775

The parabola parameters are:

a = 5, b = 210, c = - 34775

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{210}{2 \cdot 5}

Simplify

x_{v} = - 21

Plug in

x_{v} = - 21

to find the

y_{v}

value

y_{v} = - 36980

Therefore the parabola vertex is

(- 21, - 36980)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 5

Minimum (- 21, - 36980)

x^{2} - 3 x - 10

y = 4 x^{2}

3 x^{2}

x^{2} + 8 x - 5

+ 7 x^{2} + 5

What is the vertices y=5x^2+210x-34775 ?
The vertices y=5x^2+210x-34775 is Minimum (-21,-36980)