What is 2x^2+2y^2-12x+8y-24=0 ?

The solution to 2x^2+2y^2-12x+8y-24=0 is Circle with (a,b)=(3,-2),r=5

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2x^2+2y^2-12x+8y-24=0

2 x^{2} + 2 y^{2} - 12 x + 8 y - 24 = 0

(a, b) = (3, - 2), r = 5

Solution steps

2 x^{2} + 2 y^{2} - 12 x + 8 y - 24 = 0

Rewrite

2 x^{2} + 2 y^{2} - 12 x + 8 y - 24 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 2))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (3, - 2), r = 5

\frac{( x - 5 ) ^{2}}{25} + \frac{( y + 3 ) ^{2}}{9} = 1

x^{2} + y^{2} = 7

\frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{a ^{2}} = 1

x^{2} = 12 y

\frac{x ^{2}}{16} + \frac{y ^{2}}{36} = 1

What is 2x^2+2y^2-12x+8y-24=0 ?
The solution to 2x^2+2y^2-12x+8y-24=0 is Circle with (a,b)=(3,-2),r=5