What is the vertices y=-4x^2-24x-40 ?

The vertices y=-4x^2-24x-40 is Maximum (-3,-4)

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vertices y=-4x^2-24x-40

vertices

y = - 4 x^{2} - 24 x - 40

Maximum (- 3, - 4)

Solution steps

y = - 4 x^{2} - 24 x - 40

The parabola parameters are:

a = - 4, b = - 24, c = - 40

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{( - 24 )}{2 ( - 4 )}

Simplify

x_{v} = - 3

Plug in

x_{v} = - 3

to find the

y_{v}

value

y_{v} = - 4

Therefore the parabola vertex is

(- 3, - 4)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = - 4

Maximum (- 3, - 4)

f (x) = x^{2} + 6 x + 9

f (x) = - x^{2} + 2

f (x) = x^{2} + 5 x + 4

+ y^{2} + 12 x + 4 y - 32 = 0

f (x) = - 2 x^{2} - 16 x - 30

What is the vertices y=-4x^2-24x-40 ?
The vertices y=-4x^2-24x-40 is Maximum (-3,-4)