What is the vertices x=y^2-3 ?

The vertices x=y^2-3 is (h,k)=(-3,0),p= 1/4

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vertices x=y^2-3

vertices

x = y^{2} - 3

(h, k) = (- 3, 0), p = \frac{1}{4}

Solution steps

x = y^{2} - 3

Rewrite

x = y^{2} - 3

in the standard form:

4 \cdot \frac{1}{4} (x - (- 3)) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- 3, 0), p = \frac{1}{4}

y = 12 x (x - 4)

(x + 2)^{2}

y^{2} + 4 x - 2 y + 21 = 0

f (x) = 415 x^{2} - 4600 x + 200000

y = x^{2} - 4 x 3