What is the vertices 3x^2-10 ?

The vertices 3x^2-10 is Minimum (0,-10)

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vertices 3x^2-10

vertices

3 x^{2} - 10

Minimum (0, - 10)

Solution steps

y = 3 x^{2} - 10

The parabola parameters are:

a = 3, b = 0, c = - 10

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{0}{2 \cdot 3}

Simplify

x_{v} = 0

Plug in

x_{v} = 0

to find the

y_{v}

value

y_{v} = - 10

Therefore the parabola vertex is

(0, - 10)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 3

Minimum (0, - 10)

f (x) = - x^{2} + 2 x - 5

f (x) = x^{2} + 2 x + 6

f (x) = 2 x^{2} + 4 x - 6

f (x) = 10 x^{2} - 17

3 x^{2} - 5 x + 2