What is the vertices+s^2+2s+2 ?

The vertices+s^2+2s+2 is Minimum (-1,1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices+s^2+2s+2

vertices

+ s^{2} + 2 s + 2

Minimum (- 1, 1)

Solution steps

y = s^{2} + 2 s + 2

The parabola parameters are:

a = 1, b = 2, c = 2

x_{v} = - \frac{b}{2 a}

s_{v} = - \frac{2}{2 \cdot 1}

Simplify

s_{v} = - 1

Plug in

s_{v} = - 1

to find the

y_{v}

value

y_{v} = 1

Therefore the parabola vertex is

(- 1, 1)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 1

Minimum (- 1, 1)

f (x) = x^{2} + 7 x + 12

f (x) = x^{2} + 7 x + 10

y = 2 x^{2} - 3 x + 1

y^{2} - 2 y - 12 x + 25 = 0

x^{2} - 4 x - 6