What is the vertices 5x^2-10 ?

The vertices 5x^2-10 is Minimum (0,-10)

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vertices 5x^2-10

vertices

5 x^{2} - 10

Minimum (0, - 10)

Solution steps

y = 5 x^{2} - 10

The parabola parameters are:

a = 5, b = 0, c = - 10

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{0}{2 \cdot 5}

Simplify

x_{v} = 0

Plug in

x_{v} = 0

to find the

y_{v}

value

y_{v} = - 10

Therefore the parabola vertex is

(0, - 10)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 5

Minimum (0, - 10)

f (x) = 2 x^{2} - 4 x + 3

y = 18 x^{2} - 6 x + 4

f (x) = - x^{2} + 14 x - 48

f (x) = x^{2} + 11 x - 35

f (x) = 2 x^{2} + 4 x