What is the vertices y^2=5x+3 ?

The vertices y^2=5x+3 is (h,k)=(-3/5 ,0),p= 5/4

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vertices y^2=5x+3

vertices

y^{2} = 5 x + 3

(h, k) = (- \frac{3}{5}, 0), p = \frac{5}{4}

Solution steps

y^{2} = 5 x + 3

Rewrite

y^{2} = 5 x + 3

in the standard form:

4 \cdot \frac{5}{4} (x - (- \frac{3}{5})) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{5}, 0), p = \frac{5}{4}

f (x) = - 3 x^{2} + 1

f (x) = (x - 1)^{2} + 2

f (x) = x^{2} + 12 x + 16

x^{2} + 4 x - 5

- x^{2} + 3 x - 5