What is the vertices f(x)=-3x^2-18x-25 ?

The vertices f(x)=-3x^2-18x-25 is Maximum (-3,2)

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vertices f(x)=-3x^2-18x-25

vertices

f (x) = - 3 x^{2} - 18 x - 25

Maximum (- 3, 2)

Solution steps

y = - 3 x^{2} - 18 x - 25

The parabola parameters are:

a = - 3, b = - 18, c = - 25

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{( - 18 )}{2 ( - 3 )}

Simplify

x_{v} = - 3

Plug in

x_{v} = - 3

to find the

y_{v}

value

y_{v} = 2

Therefore the parabola vertex is

(- 3, 2)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = - 3

Maximum (- 3, 2)

y = 18 x^{2} - 14 x + 9

f (x) = - 3 x^{2} + 18 x - 8

y = x^{2} - 6 x + 8

y = (x - 1)^{2} - 2

y = - 4 x^{2} - 12 x - 8

What is the vertices f(x)=-3x^2-18x-25 ?
The vertices f(x)=-3x^2-18x-25 is Maximum (-3,2)