en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices x=2y^2

Solution

vertices

x = 2 y^{2}

Solution

(h, k) = (0, 0), p = \frac{1}{8}

Solution steps

x = 2 y^{2}

Rewrite

x = 2 y^{2}

in the standard form:

4 \cdot \frac{1}{8} (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{8}

Popular Examples

vertices x^2-14x+49 vertices

x^{2} - 14 x + 49

vertices y=x^2-12x+36 vertices

y = x^{2} - 12 x + 36

vertices f(x)=3x^2+1 vertices

f (x) = 3 x^{2} + 1

vertices y^2+2y+x+5=0 vertices

y^{2} + 2 y + x + 5 = 0

vertices x^2+6x+8 vertices

x^{2} + 6 x + 8

Frequently Asked Questions (FAQ)

What is the vertices x=2y^2 ?
The vertices x=2y^2 is (h,k)=(0,0),p= 1/8