What is the vertices x^2+2x-24 ?

The vertices x^2+2x-24 is Minimum (-1,-25)

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vertices x^2+2x-24

vertices

x^{2} + 2 x - 24

Minimum (- 1, - 25)

Solution steps

y = x^{2} + 2 x - 24

The parabola parameters are:

a = 1, b = 2, c = - 24

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{2}{2 \cdot 1}

Simplify

x_{v} = - 1

Plug in

x_{v} = - 1

to find the

y_{v}

value

y_{v} = - 25

Therefore the parabola vertex is

(- 1, - 25)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 1

Minimum (- 1, - 25)

y = 2 x^{2} + 12 x + 14

x^{2} - 3 x - 4

4 x^{2} - 8 x - 3 y - 2 = 0

y = - \frac{( x + 3 ) ^{2}}{20} + 1

f (x) = 2 x^{2} + 4 x - 2