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vertices y^2=40x

Solution

vertices

y^{2} = 40 x

Solution

(h, k) = (0, 0), p = 10

Solution steps

y^{2} = 40 x

Rewrite

y^{2} = 40 x

in the standard form:

4 \cdot 10 (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = 10

Popular Examples

vertices y^2=16x-8 vertices

y^{2} = 16 x - 8

vertices y=-x^2+3 vertices

y = - x^{2} + 3

vertices f(x)=(x-2)^2+3 vertices

f (x) = (x - 2)^{2} + 3

vertices y=5x^2+13x-6 vertices

y = 5 x^{2} + 13 x - 6

vertices f(x)=-x^2-4x vertices

f (x) = - x^{2} - 4 x

Frequently Asked Questions (FAQ)

What is the vertices y^2=40x ?
The vertices y^2=40x is (h,k)=(0,0),p=10