What is the vertices y^2-8x-6y-23=0 ?

The vertices y^2-8x-6y-23=0 is (h,k)=(-4,3),p=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices y^2-8x-6y-23=0

vertices

y^{2} - 8 x - 6 y - 23 = 0

(h, k) = (- 4, 3), p = 2

Solution steps

y^{2} - 8 x - 6 y - 23 = 0

Rewrite

y^{2} - 8 x - 6 y - 23 = 0

in the standard form

4 \cdot 2 (x - (- 4)) = (y - 3)^{2}

Therefore parabola properties are:

(h, k) = (- 4, 3), p = 2

g (x) = (x + 3)^{2} + 5

f (x) = - x^{2} + 4 x + 2

f (x) = x^{2} + 8 + 15

y = x^{2} + 4 x - 5

3 x^{2} + 1

What is the vertices y^2-8x-6y-23=0 ?
The vertices y^2-8x-6y-23=0 is (h,k)=(-4,3),p=2