What is the vertices y=(2x-1)(5x-6) ?

The vertices y=(2x-1)(5x-6) is Minimum (17/20 ,-49/40)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices y=(2x-1)(5x-6)

vertices

y = (2 x - 1) (5 x - 6)

Minimum (\frac{17}{20}, - \frac{49}{40})

Solution steps

y = (2 x - 1) (5 x - 6)

y = (2 x - 1) (5 x - 6)

The parabola parameters are:

a = 10, m = \frac{1}{2}, n = \frac{6}{5}

x_{v} = \frac{m + n}{2}

x_{v} = \frac{( \frac{1}{2} ) + ( \frac{6}{5} )}{2}

Simplify

\frac{( \frac{1}{2} ) + ( \frac{6}{5} )}{2} : \frac{17}{20}

x_{v} = \frac{17}{20}

Plug in

x_{v} = \frac{17}{20}

to find the

y_{v}

value

y_{v} = - \frac{49}{40}

Therefore the parabola vertex is

(\frac{17}{20}, - \frac{49}{40})

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 10

Minimum (\frac{17}{20}, - \frac{49}{40})

f (x) = x^{2} + 3 x + 4

f (x) = x^{2} + 3 x + 2

x^{2} - 6 x

x^{2} - 8 x

\frac{40 x ^{3}}{3 x}

What is the vertices y=(2x-1)(5x-6) ?
The vertices y=(2x-1)(5x-6) is Minimum (17/20 ,-49/40)