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Popular >

vertices y^2-8y+4x=0

Solution

vertices

y^{2} - 8 y + 4 x = 0

Solution

(h, k) = (4, 4), p = - 1

Solution steps

y^{2} - 8 y + 4 x = 0

Rewrite

y^{2} - 8 y + 4 x = 0

in the standard form

4 (- 1) (x - 4) = (y - 4)^{2}

Therefore parabola properties are:

(h, k) = (4, 4), p = - 1

Popular Examples

vertices 4y^2+9y^2+32x-18y+37=0 vertices

4 y^{2} + 9 y^{2} + 32 x - 18 y + 37 = 0

vertices x^2+3x+2 vertices

x^{2} + 3 x + 2

vertices y=+(x-3)^2 vertices

y = + (x - 3)^{2}

vertices 3(x-6)^2+1 vertices

3 (x - 6)^{2} + 1

vertices f(x)=(x+3)^2-2 vertices

f (x) = (x + 3)^{2} - 2

Frequently Asked Questions (FAQ)

What is the vertices y^2-8y+4x=0 ?
The vertices y^2-8y+4x=0 is (h,k)=(4,4),p=-1