What is the vertices (y-9)^2=-4(x-2) ?

The vertices (y-9)^2=-4(x-2) is (h,k)=(2,9),p=-1

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vertices (y-9)^2=-4(x-2)

vertices

(y - 9)^{2} = - 4 (x - 2)

(h, k) = (2, 9), p = - 1

Solution steps

(y - 9)^{2} = - 4 (x - 2)

Rewrite

(y - 9)^{2} = - 4 (x - 2)

in the standard form:

4 (- 1) (x - 2) = (y - 9)^{2}

Therefore parabola properties are:

(h, k) = (2, 9), p = - 1

(x + 2)^{2} = - 8 (y + 3)

y = x^{2} + 3 x + 4

y = 24 x - 3 x^{2}

(x - 5)^{2} = 4 (y - 3)

(x - 4)^{2} = 8 y + 16

What is the vertices (y-9)^2=-4(x-2) ?
The vertices (y-9)^2=-4(x-2) is (h,k)=(2,9),p=-1