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Popular >

foci y=4x^2

Solution

foci

y = 4 x^{2}

Solution

(0, \frac{1}{16})

Solution steps

Rewrite

y = 4 x^{2}

in the standard form:

4 \cdot \frac{1}{16} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{16}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + \frac{1}{16})

Refine

(0, \frac{1}{16})

Popular Examples

foci (x-2)=3(y-5)^2 foci

(x - 2) = 3 (y - 5)^{2}

foci y=6x^2-3x5 foci

y = 6 x^{2} - 3 x 5

foci+(y-2)=3(x-5)^2 foci

+ (y - 2) = 3 (x - 5)^{2}

foci-0.5x^2-3 foci

- 0.5 x^{2} - 3

foci (y-3)^2+12x=0 foci

(y - 3)^{2} + 12 x = 0

Frequently Asked Questions (FAQ)

What is the foci y=4x^2 ?
The foci y=4x^2 is (0, 1/16)