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Popular >

foci y=x^2-2x5

Solution

foci

y = x^{2} - 2 x 5

Solution

(5, - \frac{99}{4})

Solution steps

Rewrite

y = x^{2} - 2 x \cdot 5

in the standard form

4 \cdot \frac{1}{4} (y - (- 25)) = (x - 5)^{2}

(h, k) = (5, - 25), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(5, - 25)

along the y-axis

(5, - 25 + p)

= (5, - 25 + \frac{1}{4})

Refine

(5, - \frac{99}{4})

Popular Examples

foci y=x^2+3x-16 foci

y = x^{2} + 3 x - 16

foci y=(5x-7)^2-13 foci

y = (5 x - 7)^{2} - 13

foci 4x^2-12x-16y+41=0 foci

4 x^{2} - 12 x - 16 y + 41 = 0

foci 1-x-x^2 foci

1 - x - x^{2}

foci 4x^2-20x-24y+97=0 foci

4 x^{2} - 20 x - 24 y + 97 = 0

Frequently Asked Questions (FAQ)

What is the foci y=x^2-2x5 ?
The foci y=x^2-2x5 is (5,-99/4)