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Popular >

foci y=x^2+1

Solution

foci

y = x^{2} + 1

Solution

(0, \frac{5}{4})

Solution steps

Rewrite

y = x^{2} + 1

in the standard form:

4 \cdot \frac{1}{4} (y - 1) = (x - 0)^{2}

(h, k) = (0, 1), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 1)

along the y-axis

(0, 1 + p)

= (0, 1 + \frac{1}{4})

Refine

(0, \frac{5}{4})

Popular Examples

foci 290(8x+0.5x^2-1.4)foci

290 (8 x + 0.5 x^{2} - 1.4)

foci y=-3x^2-12x-9 foci

y = - 3 x^{2} - 12 x - 9

foci 2-3x^2 foci

2 - 3 x^{2}

foci x^2+5x-14 foci

x^{2} + 5 x - 14

foci x^2+8x-12y+88=0 foci

x^{2} + 8 x - 12 y + 88 = 0

Frequently Asked Questions (FAQ)

What is the foci y=x^2+1 ?
The foci y=x^2+1 is (0, 5/4)