en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci y^2+4x=7

Solution

foci

y^{2} + 4 x = 7

Solution

(\frac{3}{4}, 0)

Solution steps

Rewrite

y^{2} + 4 x = 7

in the standard form:

4 (- 1) (x - \frac{7}{4}) = (y - 0)^{2}

(h, k) = (\frac{7}{4}, 0), p = - 1

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(\frac{7}{4}, 0)

along the x-axis

(\frac{7}{4} + p, 0)

= (\frac{7}{4} + (- 1), 0)

Refine

(\frac{3}{4}, 0)

Popular Examples

foci x^2-4x foci

x^{2} - 4 x

foci (x-11)^2 foci

(x - 11)^{2}

foci 0=(y-1)^2-16(x+4)foci

0 = (y - 1)^{2} - 16 (x + 4)

foci y^2-6y-8x+17=0 foci

y^{2} - 6 y - 8 x + 17 = 0

foci-16t^2+256 foci

- 16 t^{2} + 256

Frequently Asked Questions (FAQ)

What is the foci y^2+4x=7 ?
The foci y^2+4x=7 is (3/4 ,0)