What is the foci x+7= 1/36 (y+3)^2 ?

The foci x+7= 1/36 (y+3)^2 is (2,-3)

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foci x+7= 1/36 (y+3)^2

foci

x + 7 = \frac{1}{36} (y + 3)^{2}

(2, - 3)

Solution steps

Rewrite

x + 7 = \frac{1}{36} (y + 3)^{2}

in the standard form:

4 \cdot 9 (x - (- 7)) = (y - (- 3))^{2}

(h, k) = (- 7, - 3), p = 9

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(- 7, - 3)

along the x-axis

(- 7 + p, - 3)

= (- 7 + 9, - 3)

Refine

(2, - 3)

2 y^{2} - 8 x = 0

y^{2} - 8 y + 4 x = 0

x^{2} + 20 y = 10

7 y^{2}

\frac{1}{2} x^{2}