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Popular >

foci x^2+8y=0

Solution

foci

x^{2} + 8 y = 0

Solution

(0, - 2)

Solution steps

Rewrite

x^{2} + 8 y = 0

in the standard form:

4 (- 2) (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = - 2

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + (- 2))

Refine

(0, - 2)

Popular Examples

foci y^2+6y+2x+1=0 foci

y^{2} + 6 y + 2 x + 1 = 0

foci (y+5)^2=-16(x-3)foci

(y + 5)^{2} = - 16 (x - 3)

foci (x+3)^2=-12(y+4)foci

(x + 3)^{2} = - 12 (y + 4)

foci y^2=-32x foci

y^{2} = - 32 x

foci y=8x^2-x+1 foci

y = 8 x^{2} - x + 1

Frequently Asked Questions (FAQ)

What is the foci x^2+8y=0 ?
The foci x^2+8y=0 is (0,-2)