What is the foci (x-2)^2=8(y-1) ?

The foci (x-2)^2=8(y-1) is (2,3)

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foci (x-2)^2=8(y-1)

foci

(x - 2)^{2} = 8 (y - 1)

(2, 3)

Solution steps

Rewrite

(x - 2)^{2} = 8 (y - 1)

in the standard form:

4 \cdot 2 (y - 1) = (x - 2)^{2}

(h, k) = (2, 1), p = 2

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(2, 1)

along the y-axis

(2, 1 + p)

= (2, 1 + 2)

Refine

(2, 3)

x^{2} - 2 x - 15

- 2 x^{2} - 4 x + y + 70 = 0

y = + 0.5 (x + 2) (x - 4)

y = 2.1 + 4.4 x - 0.7 x^{2}

y = x^{2} - 10 x - 4