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Popular >

foci y=2x^2-2

Solution

foci

y = 2 x^{2} - 2

Solution

(0, - \frac{15}{8})

Solution steps

Rewrite

y = 2 x^{2} - 2

in the standard form:

4 \cdot \frac{1}{8} (y - (- 2)) = (x - 0)^{2}

(h, k) = (0, - 2), p = \frac{1}{8}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, - 2)

along the y-axis

(0, - 2 + p)

= (0, - 2 + \frac{1}{8})

Refine

(0, - \frac{15}{8})

Popular Examples

foci x^2+2x-1-(2x^2-3x+6)foci

x^{2} + 2 x - 1 - (2 x^{2} - 3 x + 6)

foci-x^2+8x-12 foci

- x^{2} + 8 x - 12

foci y=x^2+5x-14 foci

y = x^{2} + 5 x - 14

foci y^2-10y-12x+13=0 foci

y^{2} - 10 y - 12 x + 13 = 0

foci y^2-4x=0 foci

y^{2} - 4 x = 0

Frequently Asked Questions (FAQ)

What is the foci y=2x^2-2 ?
The foci y=2x^2-2 is (0,-15/8)