en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci y^2=5x

Solution

foci

y^{2} = 5 x

Solution

(\frac{5}{4}, 0)

Solution steps

Rewrite

y^{2} = 5 x

in the standard form:

4 \cdot \frac{5}{4} (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = \frac{5}{4}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, 0)

along the x-axis

(0 + p, 0)

= (0 + \frac{5}{4}, 0)

Refine

(\frac{5}{4}, 0)

Popular Examples

foci 2x^2+3x-1 foci

2 x^{2} + 3 x - 1

foci y^2=7x foci

y^{2} = 7 x

foci y^2+12x-2y-11=0 foci

y^{2} + 12 x - 2 y - 11 = 0

foci y=(x+4)^2-1 foci

y = (x + 4)^{2} - 1

foci 9y^2+12x=0 foci

9 y^{2} + 12 x = 0

Frequently Asked Questions (FAQ)

What is the foci y^2=5x ?
The foci y^2=5x is (5/4 ,0)