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Popular >

foci y^2=-10x

Solution

foci

y^{2} = - 10 x

Solution

(- \frac{5}{2}, 0)

Solution steps

Rewrite

y^{2} = - 10 x

in the standard form:

4 (- \frac{5}{2}) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - \frac{5}{2}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, 0)

along the x-axis

(0 + p, 0)

= (0 + (- \frac{5}{2}), 0)

Refine

(- \frac{5}{2}, 0)

Popular Examples

x^{2} = 8 y

foci (x+6)^2+((y+4)^2)/(1/4)=1 foci

(x + 6)^{2} + \frac{( y + 4 ) ^{2}}{\frac{1}{4}} = 1

(x^2)/(25)+(y^2)/(16)=1

\frac{x ^{2}}{25} + \frac{y ^{2}}{16} = 1

vertices (y^2)/(36)-(x^2)/(64)=1 vertices

\frac{y ^{2}}{36} - \frac{x ^{2}}{64} = 1

x^{2} + (y + 2)^{2} = 4

Frequently Asked Questions (FAQ)

What is the foci y^2=-10x ?
The foci y^2=-10x is (-5/2 ,0)