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Popular >

foci y=x^2-2x+5

Solution

foci

y = x^{2} - 2 x + 5

Solution

(1, \frac{17}{4})

Solution steps

Rewrite

y = x^{2} - 2 x + 5

in the standard form

4 \cdot \frac{1}{4} (y - 4) = (x - 1)^{2}

(h, k) = (1, 4), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(1, 4)

along the y-axis

(1, 4 + p)

= (1, 4 + \frac{1}{4})

Refine

(1, \frac{17}{4})

Popular Examples

foci 4x^2-24x-30 foci

4 x^{2} - 24 x - 30

foci 3y^2-6y-x=0 foci

3 y^{2} - 6 y - x = 0

foci-2x^2-16x-25 foci

- 2 x^{2} - 16 x - 25

foci-x^2+3x=2y+3 foci

- x^{2} + 3 x = 2 y + 3

foci-x^2+10x-23 foci

- x^{2} + 10 x - 23

Frequently Asked Questions (FAQ)

What is the foci y=x^2-2x+5 ?
The foci y=x^2-2x+5 is (1, 17/4)