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Popular >

foci y=x^2+2

Solution

foci

y = x^{2} + 2

Solution

(0, \frac{9}{4})

Solution steps

Rewrite

y = x^{2} + 2

in the standard form:

4 \cdot \frac{1}{4} (y - 2) = (x - 0)^{2}

(h, k) = (0, 2), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 2)

along the y-axis

(0, 2 + p)

= (0, 2 + \frac{1}{4})

Refine

(0, \frac{9}{4})

Popular Examples

foci y=(x+3)^2 foci

y = (x + 3)^{2}

foci (x+2)^2=-8(y-1)foci

(x + 2)^{2} = - 8 (y - 1)

foci y^2=5x+3 foci

y^{2} = 5 x + 3

foci (x+3)^2=-2(y-1)foci

(x + 3)^{2} = - 2 (y - 1)

foci y=(x+1/4)(x-5)foci

y = (x + \frac{1}{4}) (x - 5)

Frequently Asked Questions (FAQ)

What is the foci y=x^2+2 ?
The foci y=x^2+2 is (0, 9/4)