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Popular >

foci y=-x^2+2

Solution

foci

y = - x^{2} + 2

Solution

(0, \frac{7}{4})

Solution steps

Rewrite

y = - x^{2} + 2

in the standard form:

4 (- \frac{1}{4}) (y - 2) = (x - 0)^{2}

(h, k) = (0, 2), p = - \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 2)

along the y-axis

(0, 2 + p)

= (0, 2 + (- \frac{1}{4}))

Refine

(0, \frac{7}{4})

Popular Examples

foci (y-5)^2=12(x+3)foci

(y - 5)^{2} = 12 (x + 3)

foci y=2x^2+16x+29 foci

y = 2 x^{2} + 16 x + 29

foci y=(x+5)^2 foci

y = (x + 5)^{2}

foci x^2+2x+6 foci

x^{2} + 2 x + 6

foci y=2x^2-4x+15 foci

y = 2 x^{2} - 4 x + 15

Frequently Asked Questions (FAQ)

What is the foci y=-x^2+2 ?
The foci y=-x^2+2 is (0, 7/4)