What is the foci-2x^2+12x-10 ?

The foci-2x^2+12x-10 is (3, 63/8)

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foci-2x^2+12x-10

foci

- 2 x^{2} + 12 x - 10

(3, \frac{63}{8})

Solution steps

Rewrite

y = - 2 x^{2} + 12 x - 10

in the standard form

4 (- \frac{1}{8}) (y - 8) = (x - 3)^{2}

(h, k) = (3, 8), p = - \frac{1}{8}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(3, 8)

along the y-axis

(3, 8 + p)

= (3, 8 + (- \frac{1}{8}))

Refine

(3, \frac{63}{8})

2 y^{2} + 8 y + x + 1 = 0

x^{2} - 4 x - 12

+ 18500 (0.09 - x^{2})

y = x^{2} + 4 x + 3

y = x^{2} + 10 x + 25