What is the directrix y^2=4x ?

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directrix y^2=4x

directrix

y^{2} = 4 x

x = - 1

Solution steps

Rewrite

y^{2} = 4 x

in the standard form:

4 \cdot 1 \cdot (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = 1

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - 1

Refine

x = - 1

(y - 7)^{2} = - 12 (x + 1)

x^{2} = - 16 y

x^{2}

\frac{( x - 3 ) ^{2}}{5} + \frac{( y - 1 ) ^{2}}{15} = 1

\frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1