en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci 4x^2+8x+6

Solution

foci

4 x^{2} + 8 x + 6

Solution

(- 1, \frac{33}{16})

Solution steps

Rewrite

y = 4 x^{2} + 8 x + 6

in the standard form

4 \cdot \frac{1}{16} (y - 2) = (x - (- 1))^{2}

(h, k) = (- 1, 2), p = \frac{1}{16}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 1, 2)

along the y-axis

(- 1, 2 + p)

= (- 1, 2 + \frac{1}{16})

Refine

(- 1, \frac{33}{16})

Popular Examples

foci y=(2x-1)(5x-6)foci

y = (2 x - 1) (5 x - 6)

foci y=x^2-5x+6 foci

y = x^{2} - 5 x + 6

foci x^2-x-56 foci

x^{2} - x - 56

foci x^2-x-20 foci

x^{2} - x - 20

foci y^2+33=-8x-23 foci

y^{2} + 33 = - 8 x - 23

Frequently Asked Questions (FAQ)

What is the foci 4x^2+8x+6 ?
The foci 4x^2+8x+6 is (-1, 33/16)